Hoosiers Begin Big Ten Play on Saturday
Feb. 1, 2008
BLOOMINGTON, Ind. - The Indiana University men's tennis team begins Big Ten play on Saturday, traveling to Iowa City for a match with the Hawkeyes. The contest is scheduled to begin at noon central time.
Indiana leads the all-time series 45-15. The Hawkeyes and Hoosiers battled twice last season, with IU winning both matches. Indiana topped the Hawkeyes (6-1), on March 25, 2007, in Bloomington. The two faced off at the Big Ten Tournament as well. There, the Hoosiers defeated Iowa 4-3.
The Hoosiers are also slated to take on a heavy dose in the non-conference schedule. Matches at Alabama (#12) and North Carolina State (#20) will force IU to go on the road and compete against a pair of top-25 squads. Kentucky and SMU also crack the top-50. Indiana is currently ranked No. 62 according to the ITA.
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